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It has to do with what data a float can hold - it can hold 1.4E-45 to 3.4E38, which means that there are certain values it cannot hold which are in between those values. For example, Math.round(99.499999f) = 100. You and I can see that when you round that number it should be 100, but a float can't hold the exact number 99.499999 and the closest number that it can see is 99.5 something. Hope this helps (I don't believe the SCJP expects you to know the rounded (integer or long) value of any float or double value). Hope this helps.
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Hi Harsha, Math . round ( Integer . MIN_VALUE - 6.5f ) == Integer . MIN_VALUE returns true because an integer can hold a minimum number -2 power of 31. Here we are rounding a value that actually should return Integer.MIN_Value-6 but an integer cannot hold such a small value so it rounds it to its minimum value Integer.MIN_VALUE. This behavior is symmetric and when we round a value that is more than Integer.MAX_Value it automatically rounds it to Integer.MAX_VALUE (ie) System.out.println(Math.round(Integer.MAX_VALUE + 1.5f)==Integer.MAX_VALUE); is true. And yes sire in case you were wondering this is the same with Long also System.out.println(Math.round(Long.MAX_VALUE + 1.5)==Long.MAX_VALUE); returns true. Hope this helps. sriram
Joined: Mar 05, 2003
Here we are rounding a value that actually should return Integer.MIN_Value-6 but an integer cannot hold such a small value so it rounds it to its minimum value Integer.MIN_VALUE
I don't believe that it's because an integer can't hold a small value - see the output from the following code:
The output will be a very large number (2.19 billion approx) because Java's numbers are signed - when you try to go too low, they loop around to be positive. I believe the answer to the question is the response I gave previously .