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Static method

Todd Bahrs

Joined: Feb 17, 2004
Posts: 7
Can someone explain why this static method is executed prior to the println
statements ? I don't understand how it gets called.
class Static {
static int b;
static int a = 3;
static void method(int x) {
System.out.println("x = " + x);
System.out.println("a = " + a);
System.out.println("b = " + b);
static { // how does this get called first ?
System.out.println("static block initialized");
b = a * 4;
public static void main(String args[]) {
method(42); // Calls the method 'method' and passes 42 to 'int x'.
Prints out:
static block initialized
x = 42
a = 3
b = 12
Richard Quist
Ranch Hand

Joined: Feb 18, 2004
Posts: 96
What you have is not a static doesn't have a method name, return type, etc...
It's a static initializer that gets executed when the class is loaded.

SCJP 1.4
Todd Bahrs

Joined: Feb 17, 2004
Posts: 7
Thanks Richard, I found a good explanation of static intializers on
sameer kumar

Joined: Mar 22, 2004
Posts: 13
hi todd
the sequence of initilization is given below remember it
when u creat object.
1. first static field(class varibles)
2. static initilizer block.
3. instance mamber
4. initilizer block
5. constructor.
normaly we read that constructor is the first stattement called.
but this is the actual happened behind this
i think it is clear now if u have any problem
call again
I agree. Here's the link:
subject: Static method
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