Overloading doubt?

[Amit Parnerkar]

Can someone help me here?
class A {void m1(A a) {System.out.print("A");}}
class B extends A {void m1(B b) {System.out.print("B");}}
class C extends B {void m1(C c) {System.out.print("C");}}
class D {
public static void main(String[] args) {
A c1 = new C(); C c2 = new C(); c1.m1(c2);
}}
The output will be "A". I understand that method m1() is being overloaded here and not inherited, hence c1.m1(c2) will invoke class A's m1() method. Just wondering if I am thinking in right direction or missing something here?

[Lionel Orellana]

I understand that method m1() is being overloaded here and not inherited

Amit, you're right about m1 being overloaded but it is being inherited too. Class C actually has the two methods it inherits from B and C and the method of its own.
The reason the method in A is the one invoked is because you have a reference of type A. It doesn't matter what the actual type of the object at runtime is. What you need to remember is this: when choosing among OVERLOADED methods check the type of the reference, when choosing among OVERRIDEN methods use the actual type of the object.
Cheers

[Alangudi Balaji Navaneethan]

Lionel what you said is correct. But I am still confusing about how you diffentiate overloading and overriding methods.

[Barry Gaunt]

Amit, take a look at marcus Green's tutorial at jchq.net