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Hi! When I compile the following code I get the value as 1 public static void main(String[ ] args) {

int k=0; k += ++k; System.out.println(k); } As per my understanding, bec's of operator precedence k becpomes 1 first and now k holds the value of 1 and then when we say k+=1 which is k=k+1(1+1) is 2.Why is it giving 1?Can anybody please explain.Thanks [ May 18, 2004: Message edited by: Barry Gaunt ]

k += ++k resolves to k = k + ++k. Taking the right hand side and evaluating left to right, you get k = 0 + ++(0). This resolves to k = 0 + 1; therefore k = 1.

Originally posted by Sridhar Srinivasan: Hi! When I compile the following code I get the value as 1 public static void main(String[ ] args) {

int k=0; k += ++k; System.out.println(k); } As per my understanding, bec's of operator precedence k becpomes 1 first and now k holds the value of 1 and then when we say k+=1 which is k=k+1(1+1) is 2.Why is it giving 1?Can anybody please explain.Thanks