This week's giveaway is in the EJB and other Java EE Technologies forum. We're giving away four copies of EJB 3 in Action and have Debu Panda, Reza Rahman, Ryan Cuprak, and Michael Remijan on-line! See this thread for details.

Hi! When I compile the following code I get the value as 1 public static void main(String[ ] args) {

int k=0; k += ++k; System.out.println(k); } As per my understanding, bec's of operator precedence k becpomes 1 first and now k holds the value of 1 and then when we say k+=1 which is k=k+1(1+1) is 2.Why is it giving 1?Can anybody please explain.Thanks [ May 18, 2004: Message edited by: Barry Gaunt ]

k += ++k resolves to k = k + ++k. Taking the right hand side and evaluating left to right, you get k = 0 + ++(0). This resolves to k = 0 + 1; therefore k = 1.

Originally posted by Sridhar Srinivasan: Hi! When I compile the following code I get the value as 1 public static void main(String[ ] args) {

int k=0; k += ++k; System.out.println(k); } As per my understanding, bec's of operator precedence k becpomes 1 first and now k holds the value of 1 and then when we say k+=1 which is k=k+1(1+1) is 2.Why is it giving 1?Can anybody please explain.Thanks