This week's giveaway is in the EJB and other Java EE Technologies forum. We're giving away four copies of EJB 3 in Action and have Debu Panda, Reza Rahman, Ryan Cuprak, and Michael Remijan on-line! See this thread for details.

0xffffffff = 1111 1111 1111 1111 1111 1111 1111 1111 since, the sight bit is one it represents a negative number.

Now 0xffffffff >> 1, i.e. signed right shift 0xffffffff >> 1 = 1111 1111 1111 1111 1111 1111 1111 1111 (u get same as previous) i.e. shift 1 bit to the right and add 1 as the most significant bit. We add one becoz we know that this number is negative (signed right shift of a negative num is always negative). Now find the decimal of this negative num i.e. take 2's complement which will be 0000 0000 0000 0000 0000 0000 0000 0000 and add 1 and remember to put a negative sign. So the result is -1