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final modifier

Grady Jamyson
Ranch Hand

Joined: Aug 04, 2002
Posts: 42
I've done the following question,
but I don't understand why the answer is "d".
Could anyone explain it?
Thanks a lot.

class JSC201 {
static byte m1() {
final char c1 = '\u0001';
return c1; // 1
static byte m2(final char c2) {return c2;} // 2
public static void main(String[] args) {
char c3 = '\u0003';
System.out.print(""+m1()+m2(c3)); // 3

What is the result of attempting to compile and run the program?

a. Prints: 13
b. Prints: 4
c. Compile-time error at 1
d. Compile-time error at 2
e. Run-time error
f. None of the above
Sachin Roham

Joined: Aug 03, 2004
Posts: 19
Hey Grady,

If u check line 1...
return c1;
an implicit cast is put there 2 convert char to byte.
this is because c1 is a compile time constant...
(its value is known at complie time ie final char c1='\u001')

but in the case of line 2...
there is a problem cause c2 is not a compile time constant...
it is a definately a constant, but its value is not known at
compile time.. as it is an argument to a method its value can
change therefore the compiler complains at line 2.

Try my simulator
Grady Jamyson
Ranch Hand

Joined: Aug 04, 2002
Posts: 42
I got it. Thanks a lot.
Barry Gaunt
Ranch Hand

Joined: Aug 03, 2002
Posts: 7729
Stoneds Brains please read the JavaRanch Naming Policy and change your displayed name accordingly.


Ask a Meaningful Question and HowToAskQuestionsOnJavaRanch
Getting someone to think and try something out is much more useful than just telling them the answer.
It is sorta covered in the JavaRanch Style Guide.
subject: final modifier