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long and float
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Mohit Agarwal
Ranch Hand
Joined: Mar 30, 2004
Posts: 88
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class A{
public static void main(String[] a){
long l=51L;
float f=2.5F;
long l1=l*f;//gives compile error
float f1=l*f;//compiles fine
}
}
When an expression involves long and float which casted to which .
Pls. let me know.
I am confused.
Mohit Agarwal
Would Be SCJP.
"The will to win is worthless if you do not have the will to prepare"
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Barry Gaunt
Ranch Hand
Joined: Aug 03, 2002
Posts: 7729
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long is converted to float so that l*f results in a float.
(Changed cast to converted)
[ October 01, 2004: Message edited by: Barry Gaunt ]
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Ask a Meaningful Question and HowToAskQuestionsOnJavaRanch
Getting someone to think and try something out is much more useful than just telling them the answer.
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Mohit Agarwal
Ranch Hand
Joined: Mar 30, 2004
Posts: 88
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Why does the compiler does this narrowing conversion.
Pls. provide more details.
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Barry Gaunt
Ranch Hand
Joined: Aug 03, 2002
Posts: 7729
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Java performs the following conversions when appropriate:
byte -> short -> long -> float -> double
(char is left out on purpose)
If one of the terms in a binary expression is a floating point number (float or double) then the other term will be converted to a floating point number so that floating point arithmetic can be performed.
The long variable l will be converted to float because a long lies within the range of a float even though the number will lose out on precision.
It's up to the programmer to allocate appropriate types to the variables if greater precision or ranges are desired. I have seen more use of doubles than floats for primitive variable types.
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subject: long and float
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