Implicit Casting

[prakash sodhani]

Hi All,

I am kind of confused with casting.

Let say if we have

float f=10;

When i executed this it works fine. My question is...if 10 is interpreted as double (64 bits)...whats the reason above assignment passed.

Same is the case with following:

long w=10;
float m=w;

When is the implicit casting done???

Thanks
Prakash

[Barry Gaunt]

The 10 is not interpreted as a double. It's an int literal constant.

The conversion is allowed because int -> long -> float is allowed. This is a widening conversion.

The constant's value 10 is small enough to fit into a float without losing any information (precision). Even if precision is lost you will not get an error.
[ November 07, 2004: Message edited by: Barry Gaunt ]

[Barry Gaunt]

Checkout Corey's Article On this Topic

[prakash sodhani]

Thanks Barry. This article seems to be what I was looking for.

-Prakash

[PNS Subramanian]

Barry,

int -> long to ok.
Is long -> float allowed ? Thought long was 8 bytes and float was 4 - could you please clarify.

[Barry Gaunt]

You too can write code:

 public class Convert
{
    public static void main(String[] args)
    {
        long x = Long.MAX_VALUE;
        float f = x;
        System.out.println(f);
        System.out.println(x);
    }
}
 

Output:

 
9.223372E18
9223372036854775807
 

[Corey McGlone]

Originally posted by Barry Gaunt:
Checkout Corey's Article On this Topic

Hehe - sometimes, Barry, I think you remember what I write better than I do. I had forgotten about that article.