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Post increment operator faux pas?

 
Gustavo Quiroz
Greenhorn
Posts: 12
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Hello. Can anyone please explain to me why Code Fragment I yields Output I while Code Fragment II yields Output II?

//Code Fragment I
int i=0;
i = i++;
System.out.println("i="+i);

//Output I
i=0

//Code Fragment II
int i=0, a=0;
a = i++;
System.out.println("a="+a);
System.out.println("i="+i);

//Output II
a=0
i=1

It seems than the JVM doesn't execute the post increment on the variable "i", but only when the LVALUE (variable on the left side of the assignment operator) is the varible "i" itself. Why?

Thanks in advance.

Gustavo Quiroz
Lima - Peru
 
Barry Gaunt
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You may find Corey's Blog Article useful.
 
Ray Stojonic
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Posts: 326
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i = i++; has been discussed many times.

It breaks down to this:
1- evaluate i, its current value is 0 so, 0 will be assigned.
2- increment i
3- assign 0 to i
 
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