the print out is just beyond my expectation

[jimmy]

System.out.println("s1==s1.toLowerCase() "+s1==s1.toLowerCase() );

[Jay Pawar]

s1.toLowerCase() returns a string which is not the same as that of s1

Meaning the reference bits of s1 is different as compared to the reference bits of the string returned by toLowerCase function.

Hence when you say s1 == s1.toLowerCase() you are comparing the bits which are unequal.

[Mike Gershman]

I think that this operator always returns false because it takes he literal String "s1==s1.toLowerCase() ", concatenates it with s1 to create a new object, then checks whether the newly created object is the same object as another newly created object which is taken from s1 but with all characters in lower case.

It never is.

I base this on + having a higher precedence than ==, so the statement is:

System.out.println( ( "s1==s1.toLowerCase() " + s1 ) == s1.toLowerCase() );

[jimmy]

mike , great job, you hit the point. thanks

[Barry Gaunt]

We've had that kinda problem before: never fails