q on strings

[JayaSiji Gopal]

What would be the output of the following code?
class A
{
B b;
A()
{
b=new B();
System.out.println(b.toString());
}
public String toString()
{
return "I am A ";
}
}
class B
{
A a;
B()
{
a=new A();
System.out.println(a.toString());
}
public String toString()
{
return "I am B ";
}
}
public class Test
{
public static void main(String[] ar)
{
A a=new A();
B b=new B();
}
}

Compile error.

Prints "I am A I am B........."
endlessly.

Prints "I am B I am A........."
endlessly.

Goes into an endless loop.

I answered 4, but the correct ans is b. Can somebody tell me y?

[Barry Gaunt]

Where did the question come from?

And please use

tags!

[Vipin Das]

Hi jayashri,
I executed this program. But no output was produced.
-vipin

[PNS Subramanian]

As expected, I get to see a StackOverflowError when executing this.

[nethanjana indrakeela]

hey,
see u'r code, frist you make counstructor A and make new object B, then that moment, invoke B constructor, but in the B constructer make object A,agian B counstructor invoke A constructor, you maked infinity loop!

if you wont, you can do it whithin one class,

class A{

void m(){System.out.println("m"); m2();}
void m2(){System.out.println("m2"); m();}

public static void main(String arg[]){


A a=new A();
a.m();
}
}



bye ,([e-mail])

[Pavan Kumat]

Would result in "StackOverflowError"