Meaningless Drivel is fun!
The moose likes Programmer Certification (SCJP/OCPJP) and the fly likes What's strictfp for? Big Moose Saloon
  Search | Java FAQ | Recent Topics | Flagged Topics | Hot Topics | Zero Replies
Register / Login
JavaRanch » Java Forums » Certification » Programmer Certification (SCJP/OCPJP)
Bookmark "What Watch "What New topic

What's strictfp for?

Edwin Dalorzo
Ranch Hand

Joined: Dec 31, 2004
Posts: 961
I have been working on the class and method identifiers. I've doing some work to use them all and understand them very well and how I may combine them without causing a compile time error.

However, still I do not understant what's the strictfp modifier for? Does it make a difference to use or not use it? Can somebody refer me to a code snippet that helps me understand?

Thanks in advance!
Barry Gaunt
Ranch Hand

Joined: Aug 03, 2002
Posts: 7729
strictfp is used if you want your program to produce identical floating point results on all platforms you run it on. If you do not use strictfp then the compiler/jvm is free to optimise the floating point arithmetic for the particular platform the program is compiled/run on.

Ask a Meaningful Question and HowToAskQuestionsOnJavaRanch
Getting someone to think and try something out is much more useful than just telling them the answer.
Mike Gershman
Ranch Hand

Joined: Mar 13, 2004
Posts: 1272
Think about this code:
float x, a, b, c;
x = a/b/c;

This is translated by the Java compiler into these expressions:
float temp = a/b;
x = temp/c;

In the general case, floating point division gives answers like 1/3 that cannot be expressed exactly in floating point, so the answers are rounded to the nearest value that can be represented in floating point format.

x, a, b, and c are always stored in IEEE-754 standard float format and look the same on any Java platform. If the hardware on your computer uses a different format, perhaps with more precision than a Java float, the Java Virtual Machine must convert the hardware format to and from the nearest IEEE-754 float value, perhaps with some loss of precision.

But what about temp. It takes extra time to convert from your hardware's format to IEEE-754 format so it makes sense to just use the hardware-format result of a/b in the temp/c operation. In addition, format conversions of intermediate results would likely lose some precision, making the final answer less precise. So Java normally leaves intermediate floating point results in local hardware format.

The problem is that different computers have different hardware floating point formats, so intermediate results are different and the final results are different. This violates the Java basic rule of machine independence.

With strictfp, every intermediate result is converted back into IEEE-754 format, then back into local hardware format for the next operation. This takes more time and costs some precision in the answer, but it results in every computer giving the same result running the same program with the same data.

Mike Gershman
SCJP 1.4, SCWCD in process
Edwin Dalorzo
Ranch Hand

Joined: Dec 31, 2004
Posts: 961
Thanks four your extraordinaryly well documented answer, Mike. That's exactly the answer I was looking for. I guess now I understand what this of strictfp is all about. I have read a lot in the JLS and JVMS, but I could not find there the simplicity and yet the profoundness of your reply.
marc weber

Joined: Aug 31, 2004
Posts: 11343

I found this section of the Java Language Specification interesting...

"We're kind of on the level of crossword puzzle writers... And no one ever goes to them and gives them an award." ~Joe Strummer
navneet shrivastava
Ranch Hand

Joined: Jul 09, 2004
Posts: 39
one more thanks to mike for such a simple & straight description

I agree. Here's the link:
subject: What's strictfp for?
jQuery in Action, 3rd edition