Ternary

[meena latha]

public class Ternary{
public static void main(String args[])
{
int a = 5;
System.out.println("Value is - " + ((a < 5) ? 9 : 9.3));
}
}

What is the resultant type of ternary operator in this program .Is it int or double???
If ternary result is to be int then why this is not throwing compile error.
As the boolean expression is false.Expression 2 is outputed which is double and double does not fit into int so it must throw compile error.
why this is not happening.
Hope my question is clear.

Thanks

[Jay Pawar]

Originally posted by ramya jp:
public class Ternary{
public static void main(String args[])
{
int a = 5;
System.out.println("Value is - " + ((a < 5) ? 9 : 9.3));
}
}

What is the resultant type of ternary operator in this program .Is it int or double???
If ternary result is to be int then why this is not throwing compile error.
As the boolean expression is false.Expression 2 is outputed which is double and double does not fit into int so it must throw compile error.
why this is not happening.
Hope my question is clear.

Thanks

The boolean expression results to false and hence the output is 9.3. Why do you think there will be problem of assigning double value to int ? I do not see that assignment here.

Morever, if you change the code as shown below.

public class Ternary{
public static void main(String args[])
{
[B]int a = 4;[/B] // changed the value
System.out.println("Value is - " + ((a < 5) ? 9 : 9.3));
}
}

The output won't be integer 9 it will be 9.0 which is double because the int 9 gets promoted to double. In ternary expresions the promotion always happens to the datatype which is wider.

Hope that helps you

[meena latha]

thanks Jay
I thought the ternary operator will defaulty take the data type of first expression.

So can i conclude by understanding that the ternary operator will take the highest datatype among exp 2 and exp3.