float 12.0/0 error

[mridul makkar]

Why float f=12.0/0 wont raise any exception.I want to know the inner reason......

[Jay Pawar]

Check out this link . Hope this helps you.

[vas vas]

Hi,

Unlike Integer class in java, Float has a field called NaN. A constant holding a Not-a-Number value of type float.

so when you do 12.0/0 , this is NaN.This is not the same with integers.You get an exception when you do 12/0 , but not whne 12.0/0.

Hope this helps.
Suman Tedla.

[Joe Borderi]

"so when you do 12.0/0 , this is NaN."

12.0/0 is POSITIVE_INFINITY. NaN results from performing Java operations that result in "Not a Number", such as taking the square root of a negative number.

java.lang.Float
public static final float MAX_VALUE           3.4028234663852886E38f
public static final float MIN_VALUE           1.401298464324817E-45f
public static final float NaN                 0f/0f
public static final float NEGATIVE_INFINITY   -1f/0f 
public static final float POSITIVE_INFINITY   1f/0f  

[Srinivasa Raghavan]

Is this even same for double ?
I mean does double has a NAN const.

[Jesse Torres]

Originally posted by srini vasan:
Is this even same for double ?
I mean does double has a NAN const.

Yes primitive double also has a NaN constant.

[Srinivasa Raghavan]

Thanks guys nice info.