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Constructor invocation?

Ramana Uppala

Joined: Jan 04, 2005
Posts: 16
In the below program why not byte or short constructor not called.

public class Test2 {
Test2(byte i)
System.out.println("in byte constructor");
}Test2(short i)
System.out.println("in short constructor");
}Test2(int i)
System.out.println("in int constructor");
}Test2(long i){

System.out.println("in long constructor");
public static void main(String args[]){
new Test2(2);
Nikhilesh Fonseca
Ranch Hand

Joined: Aug 23, 2004
Posts: 57
have you tried type casting the parameter (byte),(short),1l the correct construcotr is called. Maybe as we have deafult value of 1.1 as a double the
default value of non floating point nos is int ....I dunno really
ankur rathi
Ranch Hand

Joined: Oct 11, 2004
Posts: 3830
Because by default any un-fractional ( non-float ) number is int .
Ramana Uppala

Joined: Jan 04, 2005
Posts: 16
I agree. Here's the link: http://aspose.com/file-tools
subject: Constructor invocation?
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