Cloneable Object

[deepu Bhalotia]

class HelloExam
{
public static void main(String[] args)
{
int[][] a = {{1,2},{0,1,2},{-1,0,2}}; // 1

Object[] obj = (Object[])a.clone(); // 2



for(int i = 0; i < obj.length; i++) // 3
{
int[] ia = (int[])obj[i]; // 4
System.out.print(ia[i]); // 5
}
}
}

This Question is given in http://www.danchisholm.net/july21/mybook/chapter5/exam1ans.html.
Answer of this Question is 112. But i am not able to understand.

Can Anybody help me in this matter.
[ April 27, 2005: Message edited by: deepak bhalotia ]

[vinuharan haran]

Hi,
Clone method creates a copy of the object.so,object 'a' is cloned and is stored in 'obj' array.Now length of 'obj' array is 3.Let us go through the loop now.
when i=0,
ia=obj[0]
so ia,obj[0] refer to a[0].
hence ia[0] is same as a[0][0] which is 1.
when i=1
ia=obj[1]
ia,obj[1] refer to a[1]
so ia[1] is same as a[1][1] which is 1 again.
when i=2
ia=obj[2]
ia,obj[2] refer to a[2]
so ia[2] is same as a[2][2] which is 2
Hope this helps...

[deepu Bhalotia]

Hi Haran

Can you explain how the array length is 3?
We are making a clone of two dimensional array into one dimensional array.


Thanks
Deepak

[vinuharan haran]

Hi,
The length of array a is 3.so obj.length is also 3.That is 'a' has three elements.
Dimensional arrays are considered as array of arrays.
Now,
a has three elements which are references to other array.So a.length is 3.

a[0] is again a array of 2 elements .so,length of a[0] is 2.
length of a[1] and a[2] is 3.
Hope this helps...

[deepu Bhalotia]

Thanks Vinu....

It really Worked....

Thanks,
Deepak