# Shift Operator Dought

Dhanesh Kumar

Greenhorn

Posts: 17

posted 10 years ago

- 0

Hi friends

class EBH019 {

public static void main (String args[]) {

int i1 = 0xffffffff, i2 = i1 << 1;

int i3 = i1 >> 1, i4 = i1 >>> 1;

System.out.print(Integer.toHexString(i2) + ",");

System.out.print(Integer.toHexString(i3) + ",");

System.out.print(Integer.toHexString(i4));

}}

I know only how the int value is shifted by using any one of shift operator

Above pgm is hex value. That hex value first converted to int than it going to be shifted .am I right?

Convert to hex to int and than shifted is take more time to find the answer.

If suppose the real exam having like this means how to find a answer very fast as well as by easiest way

Please replay as soon as possible.

Preparing SCJP(1.4)

(removed shouting from topic title)

[ May 10, 2005: Message edited by: Barry Gaunt ]

class EBH019 {

public static void main (String args[]) {

int i1 = 0xffffffff, i2 = i1 << 1;

int i3 = i1 >> 1, i4 = i1 >>> 1;

System.out.print(Integer.toHexString(i2) + ",");

System.out.print(Integer.toHexString(i3) + ",");

System.out.print(Integer.toHexString(i4));

}}

I know only how the int value is shifted by using any one of shift operator

Above pgm is hex value. That hex value first converted to int than it going to be shifted .am I right?

Convert to hex to int and than shifted is take more time to find the answer.

If suppose the real exam having like this means how to find a answer very fast as well as by easiest way

Please replay as soon as possible.

Preparing SCJP(1.4)

(removed shouting from topic title)

[ May 10, 2005: Message edited by: Barry Gaunt ]

deepu Bhalotia

Ranch Hand

Posts: 39

Dhanesh Kumar

Greenhorn

Posts: 17

deepu Bhalotia

Ranch Hand

Posts: 39

posted 10 years ago

- 0

Hi friends

class EBH019 {

public static void main (String args[]) {

int i1 = 0xffffffff, i2 = i1 << 1;

int i3 = i1 >> 1, i4 = i1 >>> 1;

System.out.print(Integer.toHexString(i2) + ",");

System.out.print(Integer.toHexString(i3) + ",");

System.out.print(Integer.toHexString(i4));

}}

Hi,

Here the compile will first convert theHex number into Int and check for the number. whether this number is fit in int.

But while solving this there is no need for us to convert in int. We can directly cenvert hex number into binary and shift it.

Like...

int a=ffffffff;

So binary number for this is

1111 1111 1111 1111 1111 1111 1111 1111.

Now you can do the shifting. and again can convert in to hex easily. Since the options are also given in Hex. So i don't think that it's going to take more time.

Deepak.

class EBH019 {

public static void main (String args[]) {

int i1 = 0xffffffff, i2 = i1 << 1;

int i3 = i1 >> 1, i4 = i1 >>> 1;

System.out.print(Integer.toHexString(i2) + ",");

System.out.print(Integer.toHexString(i3) + ",");

System.out.print(Integer.toHexString(i4));

}}

Hi,

Here the compile will first convert theHex number into Int and check for the number. whether this number is fit in int.

But while solving this there is no need for us to convert in int. We can directly cenvert hex number into binary and shift it.

Like...

int a=ffffffff;

So binary number for this is

1111 1111 1111 1111 1111 1111 1111 1111.

Now you can do the shifting. and again can convert in to hex easily. Since the options are also given in Hex. So i don't think that it's going to take more time.

Deepak.

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