Wrapper Class.

[Bhalotia Kunal]

class H {
  public static void main (String[] args) {
    int i1, i2; Integer i3, i4;
    i1=new Integer(Integer.parseInt("1")).intValue();     // 1
    i3=new Integer(Integer.parseInt("1")).intValue();     // 2
    i2=Integer.parseInt(Integer.valueOf("1").toString()); // 3
    i4=Integer.parseInt(Integer.valueOf("1").intValue()); // 4
}}
 

can you please explain me which line makes a compile time error.

thanks,
Deepak

[Barry Gaunt]

What happens if you compile the code? What error message do you get? For what line?

[Bhalotia Kunal]

Hi Barry,

The Answer is...
Compile-time error at 2.
Compile-time error at 4.

Thanks
Deepak

[Vishnu Prakash]

Ans:2 and 4

Why 2? Because the return type of intValue() is int and not Integer

Why 4?
parseType(String s)

In your example

Integer.parseInt(Integer.valueOf("1").intValue())

Integer.valueOf("1").intValue() return an int. But parseInt()
expects a String as argument so compiler error.

[Barry Gaunt]

Good. Now try it with the Java 5.0 compiler.

You will see that this is one of the mock exam questions that gets broken with Java 5.0.