How are you sending it? If you're serializing, you could be having problems with differing versions of serialization between the client and server.
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Joined: Oct 16, 2001
Here is what I am using to send the Vector: URL url = new URL(getDocumentBase(), "../servlet/myservlet.Applet2Servlet?action=selectedClassifications"); URLConnection urlconnection = url.openConnection(); urlconnection.setDoInput(true); urlconnection.setDoOutput(true); urlconnection.setUseCaches(false); urlconnection.setDefaultUseCaches(false); urlconnection.setRequestProperty("Content-Type", "multipart/form-data");//Netscape Bug urlconnection.setAllowUserInteraction(false); ObjectOutputStream objectoutputstream = new ObjectOutputStream(new GZIPOutputStream(urlconnection.getOutputStream())); System.out.println("trying to send"); Vector objs = new Vector(); objs.addElement(selected); objs.addElement(expanded); objectoutputstream.writeObject(objs); objectoutputstream.flush(); objectoutputstream.close();
writeObject is part of the serialization mechanism, so it's likely that your sending serializer is incompatible with your receiving serializer. A better bet is to simply send everything as text:
where convertToObject() is a method you write to undo the "toString" on the sending side (if desired). An industrial-strength version might send the vector size as a number on the first line (preceeding the data lines) so you can optimally preallocate the Vector (or use an Array object, which is faster).
[This message has been edited by Tim Holloway (edited October 17, 2001).]