What is the range for long. I know long can hold 64 bits. Using the formula -2^bits-1 to (2^bits-1)-1 and using the calculator I calculate the range to be: -9223372036854775808 to 9223372036854775808
But on compile it says that this is out of range. Could someone please give me the correct range for long and let me know what is wrong here.
Many thanks, Fes D Gaur
Fes D Gaur
posted 10 years ago
Gadzooks! I figured it out. I have to have L after or l after the number. Then it works. I guess just like any floating point number is automatically assumed to be double and to change it to float an f or F is needed in the same way to take on a number larger than the integer range and to put it into a long type variable the L is needed at the end of the literal.