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usha prithvi
Ranch Hand

Joined: Jun 22, 2005
Posts: 31
In the following code,i am unable to understand the error. can someone expalin me the error.

public class SuperSubCatch {

public static void main(String[] args) {
int a = 0;
int b = 43/a;

}catch(ArithmeticException e){
System.out.println(" generic exception catch ");
}catch (ArithmeticException e){
System.out.println(" this is never reached");

shetal bansal
Ranch Hand

Joined: May 09, 2005
Posts: 63
You are catching the same exception twice.If you remove the second catch statement or chanage it to catch(Exception e), the code will work.
usha prithvi
Ranch Hand

Joined: Jun 22, 2005
Posts: 31
thankz for ur response
subject: supersubcatch
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