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supersubcatch
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usha prithvi
Ranch Hand
Joined: Jun 22, 2005
Posts: 31
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hi, In the following code,i am unable to understand the error. can someone expalin me the error. public class SuperSubCatch { public static void main(String[] args) { try{ int a = 0; int b = 43/a; }catch(ArithmeticException e){ System.out.println(" generic exception catch "); }catch (ArithmeticException e){ System.out.println(" this is never reached"); } } } thanks usha
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shetal bansal
Ranch Hand
Joined: May 09, 2005
Posts: 63
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You are catching the same exception twice.If you remove the second catch statement or chanage it to catch(Exception e), the code will work.
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usha prithvi
Ranch Hand
Joined: Jun 22, 2005
Posts: 31
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thankz for ur response
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subject: supersubcatch
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