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supersubcatch

usha prithvi
Ranch Hand

Joined: Jun 22, 2005
Posts: 31
hi,
In the following code,i am unable to understand the error. can someone expalin me the error.

public class SuperSubCatch {

public static void main(String[] args) {
try{
int a = 0;
int b = 43/a;

}catch(ArithmeticException e){
System.out.println(" generic exception catch ");
}catch (ArithmeticException e){
System.out.println(" this is never reached");
}
}
}

thanks
usha
shetal bansal
Ranch Hand

Joined: May 09, 2005
Posts: 63
You are catching the same exception twice.If you remove the second catch statement or chanage it to catch(Exception e), the code will work.
usha prithvi
Ranch Hand

Joined: Jun 22, 2005
Posts: 31
thankz for ur response
 
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subject: supersubcatch
 
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