Plz explain me the code

public class Test{
public static void main(String []args){
int [] [] [] x=new int[3][][];
int i, j;
x[0]=new int[4][];
x[1]=new int[2][];
x[2]=new int[5][];
for(i=0;i<x.length;i++)
for(j=0;j<x[i].length;j++){
x[i][j]=new int[i+j+1];
System.out.println("size="+x[i][j].length);
}
}
}

how many lines of output will be produced?(choose one)
A.7
B.9
C.11
D.13
E.Compilation fails
F.An exception is thrown at run tim

Ans: C

Plz explain me the code

Hi TR. Welcome to JavaRanch (the best site on the planet)

.

What is it you don't understand about the code?

the way of the for loop..execution.

Basically we have a three dimensional array, which is nothing more than an array of an array of an array.

The first loop goes through the first array, which holds a 2D array.
The second loop goes through the second array and constructs a third array at the index of [i][j]. Then it simply prints out the length of the newly created 3D arrays.

hth.

Cheers, Marzo.

Thank u.. But How the output be 11? plz explain me..

The nested loop (the second one) goes through each element of the second array. So the first iteration of the outter loop (on x[0]) will cause the inner loop to 4 times (x[i].length), then 5 times, then 2. 11 LINES of out put all up.

Maybe i didn't explain myself properly, it's just that my boss is walking around and i pause, then unpause the explanation.

x[0].length = 4
x[1].length = 2
x[2].length = 5

Thank U.. Marzo Kaahn .. I got it..