i implemented interface in anonymous class then it shows compiler error why

[nagaraj raja]

 class t{
void show(){

}
}
class scjp{
void vocher(){
System.out.println("vno");
}
}
interface value{
void price();
}
public class _test{

public static void main(String[] args){
t o=new t()implements value{//error 
public void price(){
System.out.println("no limit");
}
};

o.price();
}
}
 
 

 C:\test>javac _test.java
_test.java:17: ';' expected
                        t o=new t()implements value{
                                   ^
1 error
 

[marc weber]

An anonymous class can either extend another class or implement a single interface. But not both, as you are trying to do.

Note that an anonymous class does not explicitly use "extends" or "implements." Instead, the instance of the anonymous class (defined by the body you include after the constructor call) is automatically upcast to the type of the class or interface that you specify after "new."

So you could do either of the following...

Value v = new Value() {
  //...anonymous definition implements Value interface
};
 
T t = new T() {
  //...anonymous definition extends class T
};

[Marilyn de Queiroz]

_test.java:17: ';' expected
                        t o=new t()implements value{
                                   ^
1 error

Move "implements value" up to the 't' class declaration.

class t implements value {
  void show() {
  }
}

[Barry Gaunt]

If you do what Marilyn suggests then t must implement the method price or t must be abstract and declare price as an abstract (unimplemented) method.