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Illegal character ??
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srikanth reddy
Ranch Hand
Joined: Jul 28, 2005
Posts: 252
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hi friends , i have some doubt in this declaration i.e.. char a = '\u000A' why is giving output as Illegal character ??? thanks srikanth
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Thanks & Regards<br /> <br />-Srikanth
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madhu cm
Greenhorn
Joined: Jun 26, 2005
Posts: 20
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To clear your doubt.... visit this page < http://www.particle.kth.se/~lindsey/JavaCourse/Book/Part1/Java/Chapter09/characterEncodng.html [ September 09, 2005: Message edited by: madhu cm ]
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Raghu Shree
Ranch Hand
Joined: Mar 18, 2005
Posts: 143
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when we compile the java file the source is converted from default encoding to unicode. At that time unicode chars like \Uxxx are replaced with the corresponding character. After that the source file is compiled. Here \u000a is a new line character like '\n'. so String newline="\u000A" would be replaced like below newline=" "; So compiler shows the error message unclosed string literal
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Raghu J<br />SCJP 1.4<br /> <br />The Wind and waters are always<br />on the side of the ablest navigators.<br /><a href="http://groups.yahoo.com/group/scjp_share" target="_blank" rel="nofollow">SCJP Group</a><br /><a href="http://groups.yahoo.com/group/JavaBeat_SCWCD" target="_blank" rel="nofollow">SCWCD Group</a>
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madhu cm
Greenhorn
Joined: Jun 26, 2005
Posts: 20
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Unicode escape characters, of the form '\Uxxxx', where xxxx is a hexadecimal value, are processed very early in the translation process (See JLS ?3.10.4). As a result, the special characters '0A', line feed and '0D', carriage return are interpreted literally as 'end of line'. The expression: char A = '\u000A'; therefore becomes char A =; which results in a compile-time error. To avoid this error, always use the special escape characters '\n' (line feed) and '\r' (carriage return);
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subject: Illegal character ??
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