somebody pls explain why this code does not give an exception

[altaf mulla]

public class Test19{
public static void main(String args[]){
System.out.println(method());
}
public static int method(){
try{
throw new Exception();

}
catch(Exception e){
throw new Exception();

}
finally{

return 3;


}
}
}

[Steve Morrow]

It doesn't throw an exception because of the order in which the finally block is executed. The finally block is executed before the method returns. Since you return a value from finally, the method never gets to propagate that last exception.

Practically speaking, one should not return values or throw exceptions from a finally block.