Although constructors are not inherited yet they aare called implicitly by run time system or explicitly by U
<i>--Agrah Upadhyay--</i><br />Final Year B.Tech SCJP,SCWCD,SCBCD <br /> <br /><b>Now since the real test for any choice is having to make the same choice again,knowing full well what it might cost.</b>-Oracle
This seems tricky. Guess, if I have a "private" constructor and inherit a subclass from it. Now, when I would instantiate a sub-class sub-class constructor will be called which will in-turn call super class constructor, but is that accessible???