| Author |
Literals assignements
|
John Blutarsky
Greenhorn
Joined: Jun 24, 2005
Posts: 5
|
|
Why
byte i = 123; //(integer)
compile and
int i = 123L; //(long)
not compile?
|
 |
Raghuveer Kumarakrishnan
Ranch Hand
Joined: Mar 13, 2005
Posts: 32
|
|
|
byte holds upto 127 so 123 is small enough for a byte
|
Raghu<br />SCJP 1.4<br />SCWCD 1.4<br />SCBCD 1.3
|
|
Akhilesh Trivedi
Ranch Hand
Joined: Jun 22, 2005
Posts: 1493
|
|
Hi john!
Whether it be 123 or 143
All integral numbers are "int" by default.
Similary remember this all floating points be it 12.3 or 89.7382 they are "double" by default.
Integers can be assigned to byte, short or character provided they are in their acceptable range. Your case, 123 fits in byte so ok.
Next is trying to fit a "long" into an "int" which is not possible. Hope this helps...
http://java.sun.com/docs/books/jls/third_edition/html/conversions.html#5.1.2
|
Keep Smiling Always — My life is smoother when running silent. -paul
[FAQs] [Certification Guides] [The Linux Documentation Project]
|
|
 |
|
|
subject: Literals assignements
|
|
|
0
