Constructors??

[srikanth reddy]

import java.io.IOException; 
public class Question72 
{ 
    public Question72() throws IOException 
    { 
        throw new IOException(); 
    } 
}
Assume that the defination of Question72E begins with the line 
    public class Question72E extends Question72 
It is required that none of the constructors of Question72E should throw any checked exception. 
1.It can be achived by placing the call to the superclass with  a super keyword , which is placed in a try block with a catch block to handle the IOException thrown by the super class. 
2.It can be achived by avoiding explicit calls to the base class constructor. 
3.It cannot be done in the Java Laungage with the above definition of the base class.  

frnds,
without the constructor of the subclass throwing IOException..can i use keep the super in try catch block...
why 1 is not correct..

please explain..

[A Kumar]

Hi...

super() must be the first statement in a constructor ...if you are trying to
write it yourself..

Below code gives compilation error ...stating that super should be the first statement in a constructor

  
public class Question72E extends Question72 {
public Question72E(){
  try{
     super();
    }catch(IOException e){
      }
 }
}

Hope you got it

Whats the answer given in the source ....of this question..

Regards
[ November 04, 2005: Message edited by: A Kumar ]

[srikanth reddy]

thanks kumar...i forgot this concept only...i suppose the answer was it could not be done ....without the subclass throwing the exception ...
thanks