compile time error

[A Kumar]

I am getting some compile time errors .I am using 1.4
can any one help me
Thanks in advance

public class Ex04 {

  public static void main (String args[]) {
    int h = 0, i = 0, j = 0, k = 0;
label1:
System.out.println("label1:");
    for (; :wink:  { h++;
label2:
         System.out.println("label2:");
      do { i++; k = h + i + j;
        switch (k) {
          default: break label1;
          case 1: continue label1;
          case 2: break;
          case 3: break label2;
          case 4: continue label2;
          case 5: continue label1;
        }
      } while (++j < 5);
    
    }
    System.out.println(h + "," + i + "," + j);
}
  }
  

[A Kumar]

The first for loop is an empty one

for(;

[Krishna Latha Grandhi]

Hi kumar,

As per my knowledge we can only place the labels just before loops.

 public class Ex04 {

  public static void main (String args[]) {
    int h = 0, i = 0, j = 0, k = 0;
//label1: illegal
//System.out.println("label1:");
  label1:  for (; :wink:  //right
{ 
h++;
//label2: illegal
//System.out.println("label2:");
label2 :mrgreen: o {  // right
  i++; 
  k = h + i + j;
        switch (k) {
          default: break label1;
          case 1: continue label1;
          case 2: break;
          case 3: break label2;
          case 4: continue label2;
          case 5: continue label1;
        }
      } while (++j < 5);
 
    }
    System.out.println(h + "," + i + "," + j);
}
  } 

[A Kumar]

we can only place the labels just before loop

Just Comment out the inside of switch loop and try...it doesnt give any compile time error

 
 

 

 

 
public class SwitchLoop {
 


  public static void main (String args[]) {
    int h = 0, i = 0, j = 0, k = 0;
label1:
System.out.println("label1:");
    for (; :wink:  { h++;
label2:
       System.out.println("label2:");
      do { i++; k = h + i + j;
        switch (k) {
         /* default: 
          break label1;
          case 1:          
          continue label1;
          case 2:
          break;
          case 3: 
          break label2;
          case 4: 
          continue label2;
          case 5:
          continue label1;*/
        default :
        System.out.println("Inside do");
        }
      } while (++j < 5);
    }
 //   System.out.println(h + "," + i + "," + j);
}
}
 

 

 

 

 
 

Regards

[Krishna Latha Grandhi]

Hi kumar,

We can place labels before any statment. But we can able to jump to outside of the loop by identifying the loop with label.

goto like jumps is not possible in java.

The outer label should appear just before the loop begins. It does not
matter if it is on the same line or not.
From K&B book

Hope u understood

Regards
krishna

[A Kumar]

Thanks Krishna ..Got it..

[Barry Gaunt]

Is this something specifically do do with SCJP? If not, please consider posting such topics in our Java In General forums. Just because you are studying for SCJP it does not mean you should post every Java issue you have in this forum.
Thanks
-Barry