package

[xie li]

1 package test1;
2 public class Test1 {
3 static int x = 42;
4 }

1 package test2;
2 public class Test2 extends test1.Test1 {
3 public static void main(String[] args) {
4 System.out.println("x = " + x);
5 }
6 }
What is the result?
A. x = 0
B. x = 42
C. Compilation fails because of an error in line 2 of class Test2.
D. Compilation fails because of an error in line 3 of class Test1.
E. Compilation fails because of an error in line 4 of class Test2.

[Karu Raj]

hi

Where do get so many question? Do let me know please

[Shawnne James]

The answer is E. The member class variable x is declared using the default access modifier in class Test1 so it is visible only inside the package test1. Trying to access it in class Test2(found in package test2) will generate a compilation error.

Shawnne

[Balaji Sampath]

If the Class test1 is modified as follows:
package test1;
2 public class Test1 {
3 public static int x = 42;
4 }

then the answer would be:
choice: B.

Correct me if i am wrong..
regards
Balaji.S

[Naresh Gunda]

If the Class test1 is modified as follows:
package test1;
2 public class Test1 {
3 public static int x = 42;
4 }

then the answer would be:
choice: B.

Yes, public members are accessible in every class, every package
Regards
Naresh

[cathymala louis]

Hi

Since the program has

static x = 42;

I think there should be an compiler error at line 4. So I think the option E is correct.

Please correct me if I am wrong.

[vivekkumar sharma]

Originally posted by Balaji Sampath:
If the Class test1 is modified as follows:
package test1;
2 public class Test1 {
3 public static int x = 42;
4 }

then the answer would be:
choice: B.

Correct me if i am wrong..
regards
Balaji.S

Hi Balaji,

even protected static int x = 42; will work,
and i think it is better to make memebers protected if possible than to make public ,otherwise u will be un necessarily opening doors to ur class,which is not desierd

Vivek

[xie li]

thank u