Initialization Related Prob

[Shalini Banerjee]

interface I
{
int i = 1, ii = Test.out("ii", 2);
}
interface J extends I
{
int j = Test.out("j", 3), jj = Test.out("jj", 4);
}
interface K extends J
{
int k = Test.out("k", 5);
}
class Test
{
public static void main(String[] args) { System.out.println(K.j); }
public static int out(String s, int i)
{
System.out.println(s + "=" + i);
return i;
}
}

why the answer is,
j=3
jj=4
3


please explain.

[Niranjan Deshpande]

hi shalini,

you wont get such exams in the exam. this question has been posted previously on javaranch.

the exma tests you on how better you understand the objectives and not on the runtime and compile time behaviour of a code containinig interfaces

so ignore this code

[Shalini Banerjee]

Ok...thnx for your suggesion.
But still i want the explanation from somebody who can explain it.

[Chandrakanth]

The reference to K.j is a reference to a field actually declared in interface J that is not a compile-time constant, this causes initialization of the fields of interface J, but not those of its superinterface I, nor those of interface K. Despite the fact that the name K is used to refer to field j of interface J, interface K is not initialized.

you can refer to this link to know more on this:JLS
http://java.sun.com/docs/books/jls/third_edition/html/execution.html#12.4