This week's book giveaway is in the OO, Patterns, UML and Refactoring forum. We're giving away four copies of Refactoring for Software Design Smells: Managing Technical Debt and have Girish Suryanarayana, Ganesh Samarthyam & Tushar Sharma on-line! See this thread for details.
| operator has higher precedence compared to && so in the forst case && is the last one to be executed and since b1 is false answer will be false irrespective of wat comes on the rhs of && .
in the second case precedence of & is more than | . so b1&b2 is evaluated first . this gives false then new expression becomes:: false|b2 & b3 | b4 now since & has higher prcedence over | b2&b3 is evaluated . this gives true
so now expression becomes :: false|true|b4
now since binary operators are left associative false|true is evaluated . this gives true so final exppression to be evaluated is :: true|b4 which gives true
gives a compile time error. says operator & cannot be applied to Boolean and boolean
I created b1 as
Boolean b1 = new Boolean(false); as it does not allow me to create a Boolean object like this:
Boolean b1= false;
Will anyone plz clarify
It doesn't work if you are using java 1.4 or below. With java 1.5, the autoboxing and unboxing allows a boolean value to be directly assigned to a Boolean and for Boolean objects to be used with the & and | operators.
Joined: Jan 19, 2006
Just in addition to previous posts, after reading Steven's post I could realize that the precedence for logical operators are :