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Regarding Looping...

 
Greenhorn
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class JMM114 {
public static void main (String[] args) {
int i = 0, j = 0;
while (i++ < 3) do
System.out.print(j);
while (j++ < 3);
}}

i get answer as 121212
Plz explain me how the flow goes...
 
Ranch Hand
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Anish,
That program prints 12345
Are you missing a do bit of the second do-while?
[ March 03, 2006: Message edited by: Tamara Lopez ]
 
Anish Nagraj
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sorry.... that was a differnt one... the actual one is

class JMM113 {
public static void main (String[] args) {
int i = 0, j = 0, k = 0;
do while (i++ < 3)
System.out.print(k++);
while (j++ < 3);
}}

for which i get 121212...
plz explain
 
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Hi,

Your outout is wrong...please check it again its

012345
 
Seema Ahuja
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Hello Anish,

answer to your second problem is worng too...the correct answer is
012

please check again

Thanks
 
Anish Nagraj
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I am really really sorry...
here is the actual culprit...

class JMM112 {
public static void main (String[] args) {
int j = 0;
for (int i = 0; i++ < 2 do
System.out.print(i);
while (j++ < 2);
}}

i am not clear with any of such lopps... which was there in all the previous examples... plz explain me this one...
 
Tamara Lopez
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Anish,
a do while look will always do something once, and then repeat it only if the while isnt satisfied. so step by step

class JMM112 {
public static void main (String[] args) {
int j = 0;
for (int i = 0; i++ < 2; ) do
System.out.print(i);
while (j++ < 2);
}}

int j = 0
int i = 0
- enter for loop#1
i is 0 which is < 2. i++ so i is now 1 after comparison (post-suffix)
- do while until j++ < 2
print 1
j is 0 which is < 2. j++ so j is now 1 after comparison
back to do
print 1
j is 1 which is < 2. j++ so j is now 2 after comparison
print 1
j is 2 which is NOT < 2. Let's go back to for loop

- i is 1. 1 < 2. i is 2 after comparison
enter do.
print 2
j is NOT less than 2
back to for loop
- i is 2. 2 < 2 is FALSE. out of for loop
 
Tamara Lopez
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and it prints 1112
is this the bit of code you wanted?
 
Greenhorn
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Hi!

I don't know if you understood why the first output is 012345. The ideia of all examples are the same. Take a look at code:



FIRST STEP: in the first interaction we have the following setting:
==> i=0
==> at line 5 we compare if i is less than 3 (remember i is 0). The answer is true, then i = i+1 (i++) and go to the line 6.
==> then I going to print the j value until j=3!! At instruction do/while we first print the value of j (line 7), then we compare if j is less than 3(line 8), and after we increment j (j++).

Then the output for the first interaction is: j=0 j=1 j=2 j=3



SECOND STEP: in the second interaction we have the following setting:
==> i=1
==> at line 5 we compare if i is less than 3 (remember i is 1). The answer is true, then i = i+1 (i++) and go to the line 6.
==> then we print the j value (j=4). J is gratter than 3, then we increment j (j++) and came back to while(i++<3) at line 5.

Then the output for the second interaction is: j=4



LAST STEP: in the last interaction we have the following setting:
==> i=2
==> at line 5 we compare if i is less than 3 (remember i is 2). The answer is true, then i = i+1 (i++) and go to the line 6.
==> then we print the j value (j=5). J is gratter than 3, then we increment j (j++) and came back to while(i++<3) at line 5.

Then the output for the last interaction is: j=5



Now i=3, then while loop fails, the program ends and output is 01245!!!


Regards,
Marcella Spiropulos
 
Anish Nagraj
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Thanks a lot
 
With a little knowledge, a cast iron skillet is non-stick and lasts a lifetime.
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