Question on Anonymous Inner class

[Anuradha Prasanna]

Hi,

I want to know how to access a method, which is written inside an anonymous inner class.

eg) class xxx {

//Code for class

public void myMethod(){
//ActionListener is an interface
new ActionListener(){
{ //initializer
System.out.println("Inside the Anonymous Inner Class.");
}

public void anonymousMethod()
{
System.out.println("Entered anonymousMethod() inside the anonymous class.");
}

} //Anonymous Inner class Ends
} //myMethod Ends
} //class Ends

How to access the method, anonymousMethod(), so that the, System.out.println("Entered anonymousMethod() inside the anonymous class."); will be printed?

Can any of you ranchers clarify me the same?

Thanks,
Anu.

[Rajasekar Elango]

You have to assign your class to a variable to call its method..

 
class xxx {
 
//Code for class
 
public void myMethod(){
//ActionListener is an interface
ActionListener l = new ActionListener(){
{ //initializer
System.out.println("Inside the Anonymous Inner Class.");
}
 
public void anonymousMethod()
{
System.out.println("Entered anonymousMethod() inside the anonymous class.");
}
 
} //Anonymous Inner class Ends
 
//call ur method 
l.anonymousMethod();
} //myMethod Ends
} //class Ends 
 

Regards,
Raja

[mambe nanje]

well I think anonymous inner classes are created by extending the class u are instantiating and if u define any method that cannot be accessed by the reference type then u cant call the method due to the fact that at compile time the methods that can be called on an object is being determined by the reference type.

[Anuradha Prasanna]

hi,

Thanks for the clarifications.
So we can create reference variables for the class or interface we are extending while creating anonymous inner classes.
and the method iam writing inside the anonymous inner class are the ones defined in these extending class or interface. In other words i can only override the methods of the extending class or interface? and cannot write any other new methods not defined in the parent class or interface iam extending?

Thanks again,
Anu.