# shift opeartors - need help

Vidya Ramachandran

Greenhorn

Posts: 24

posted 9 years ago

- 0

hello,

i have some doubts on the operations of shift operators... Can some one

pls answer how we get sucha result.

a) public class test {

public static void main(String args[]) {

byte x = 3;

x = (byte)~x;

System.out.println(x);

}

}

The answer is -4

b) public class test {

public static void main(String args[]) {

int x;

x = -3 >> 1;

x = x >>> 2;

x = x << 1;

System.out.println(x);

}

}

The answer is 2147483646

c) public class test {

public static void main(String args[]) {

int i = -1;

i = i >> 1;

System.out.println(i);

}

}

The answer is -1

Basically i have a doubt as how the negative numbers like -3 etc will

be represented in binary. Also how the ~ works.

please help me folks...

i have some doubts on the operations of shift operators... Can some one

pls answer how we get sucha result.

a) public class test {

public static void main(String args[]) {

byte x = 3;

x = (byte)~x;

System.out.println(x);

}

}

The answer is -4

b) public class test {

public static void main(String args[]) {

int x;

x = -3 >> 1;

x = x >>> 2;

x = x << 1;

System.out.println(x);

}

}

The answer is 2147483646

c) public class test {

public static void main(String args[]) {

int i = -1;

i = i >> 1;

System.out.println(i);

}

}

The answer is -1

Basically i have a doubt as how the negative numbers like -3 etc will

be represented in binary. Also how the ~ works.

please help me folks...

Sreeram Desigan

Greenhorn

Posts: 23

posted 9 years ago

- 0

Dear Smarty,

In java -ive numbers are represented in twos compliment arithmetics. That is the binary representation of a number can be obtained by inverting the bit representation of the number and adding 1 to the result. Thus -3 will be represented as-

3 in binary is 00000011

now for - 3 invert the bits first

which will be 11111100

now add 1 to the result. thus 11111101 this is the binary reprentation of -3 in a 8 bit format. (i took 8 bits for ease of representation).

Bitwise operators are very easy to use i will tell u some basic rules of finding the results.

~x = (-x)-1 // this rule is always true thus ~3 = (-3) -1 = -4

x >>n = x/(2 power of n)// 9>>2 = 9 / (2 power 2) = 9/4 = 2;

x<<n = x * (2 power of n)//

Please let me know if further clarifications are required.

In java -ive numbers are represented in twos compliment arithmetics. That is the binary representation of a number can be obtained by inverting the bit representation of the number and adding 1 to the result. Thus -3 will be represented as-

3 in binary is 00000011

now for - 3 invert the bits first

which will be 11111100

now add 1 to the result. thus 11111101 this is the binary reprentation of -3 in a 8 bit format. (i took 8 bits for ease of representation).

Bitwise operators are very easy to use i will tell u some basic rules of finding the results.

~x = (-x)-1 // this rule is always true thus ~3 = (-3) -1 = -4

x >>n = x/(2 power of n)// 9>>2 = 9 / (2 power 2) = 9/4 = 2;

x<<n = x * (2 power of n)//

Please let me know if further clarifications are required.

Keith Lynn

Ranch Hand

Posts: 2399

posted 9 years ago

The bit value of the byte 3 is

00000011

~ is the complement operator

The result of ~3 is

11111111111111111111111111111100

Casting it to a byte we get

11111100

Which is the representation of -4.

The representation of -3 is

11111111111111111111111111111101

The first shift gives

11111111111111111111111111111110

The second shift gives

00111111111111111111111111111111

The third shift gives

01111111111111111111111111111111

The value is

Integer.MAX_VALUE

The bit representation of -1 is

11111111111111111111111111111111

The shift gives

11111111111111111111111111111111

which is -1.

Negative numbers are stored using 2's complement.

- 0

a) public class test {

public static void main(String args[]) {

byte x = 3;

x = (byte)~x;

System.out.println(x);

}

}

The bit value of the byte 3 is

00000011

~ is the complement operator

The result of ~3 is

11111111111111111111111111111100

Casting it to a byte we get

11111100

Which is the representation of -4.

b) public class test {

public static void main(String args[]) {

int x;

x = -3 >> 1;

x = x >>> 2;

x = x << 1;

System.out.println(x);

}

}

The representation of -3 is

11111111111111111111111111111101

The first shift gives

11111111111111111111111111111110

The second shift gives

00111111111111111111111111111111

The third shift gives

01111111111111111111111111111111

The value is

Integer.MAX_VALUE

c) public class test {

public static void main(String args[]) {

int i = -1;

i = i >> 1;

System.out.println(i);

}

}

The bit representation of -1 is

11111111111111111111111111111111

The shift gives

11111111111111111111111111111111

which is -1.

Negative numbers are stored using 2's complement.

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