A Static Question which is worth to know

[santhosh Gopalakrishna Bajja]

class staticTest
{
static {
int x=10;
}
static int x; // Initialize a value and check what happens
static int y;
public static int getstatic(int x){
y=x++ + ++x + ++y;
return y;
}
public static void main(String[] args) {

// int x=0; // #10
System.out.println(" Passing -1 then " + getstatic(-1)); // #1
System.out.println(" Passing 0 then " + getstatic(0)); // #2
//System.out.println(" Passing -1 then " + getstatic(-1)); // #3
//System.out.println(" Passing -1 then " + getstatic(-1)); // #4

System.out.println(x); //#5
System.out.println(y); //#6

staticTest t1= new staticTest(); //#7
System.out.println(t1.x); //#8
System.out.println(t1.y++); //#9

}
}


// Guys Hope so u will enjoy....
// Don't be fooled seeing such kind of Questions.
// Don't be Hurry. We know things but if we are urgent to complete the Exam things goes wrong
// I was wrong during taking a mock exam after analying why am i wrong things came out like this.
// I hope this will even help u
// Correct me if i am wrong

// #1 if x = -1 then -1 + 1 + 1 = 0 i.e y is 1;
// #2 if x = 0 then 0 + 2 + 2 = 4 i.e y is 4
// #3 if x = -1 then -1 + 1 + 5 = 0 i.e y is 5;
// #4 if x = -1 then -1 + 1 + 6 = 0 i.e y is 6;

// #5 x is 0
// #6 y is 6

// Copy the line #7, #8, #9 above #1 and see the fun....

// Remove the comment at #10 and Enjoy

// Things to observer. x variable in getStatic method is local variable.
// Y is a class variable.
// Exam Creators will confuse us with same name which they have defined as member variable.


// I have learned a good lesson and wish to share with u .....................................

// Correct me if i am wrong anywhere............. I will learn.



Santhosh

[Asha Pathik]

Good One.

Asha

[Aum Tao]

Just one correction.

staticTest should be StaticTest.

[Aum Tao]

Thanks for sharing.
[ April 21, 2006: Message edited by: Aum Tao ]

[Aum Tao]

// #1 if x = -1 then -1 + 1 + 1 = 0 i.e y is 1;

If i am right, the correct breakup is

if x = -1, then 0 + 0 + 1 = 1 and y is returned as 1.

Due to the pre increment operator ( ++x) x = -1 becomes 0 and hence the above result.

[Aum Tao]

// #1 if x = -1 then -1 + 1 + 1 = 0 i.e y is 1;

If i am right, the correct breakup is

if x = -1, then 0 + 0 + 1 = 1 and y is returned as 1.

Due to the pre increment operator ( ++x) x = -1 becomes 0 and hence the above result.

[santhosh Gopalakrishna Bajja]

Originally posted by Aum Tao:


If i am right, the correct breakup is

if x = -1, then 0 + 0 + 1 = 1 and y is returned as 1.

Due to the pre increment operator ( ++x) x = -1 becomes 0 and hence the above result.

#1. X=-1 Then

y = x++ + ++x + ++y
y = -1 + 1 + 1 Y= 1

Let's see how

y = x++ + ++x + ++y

x++ --> value of x. i.e x = x + 1; this is a statement and after this x is 0 but as this is post increment the increment vlaue will not be taken. the value taken in the expression is -1

++x --> Increment value of x. ie x= 0 + 1 = 1. Preincrement value is taken as a input.

++y --> member variable. by default assigned to 0 ie Preincrement hence input value is 1

.'. -1 + 1 + 1 = 1

y = 1;


santhosh
[ April 21, 2006: Message edited by: santhosh Gopalakrishna Bajja ]

[sirisha sirisha]

this program gives a compiler error, i know that there should be one public class in a file and it should match with the ame of the file.but are there any restrictions on using protected?
import java.util.*;

public class newtree extends newtreeset {

public static void main(String [] args) {
newtree t = new tree();
t.count();
}
}

protected class newtreeset {
void count() {

System.out.println("yes");
}

}

[santhosh Gopalakrishna Bajja]

Originally posted by sirisha sirisha:
this program gives a compiler error, i know that there should be one public class in a file and it should match with the ame of the file.but are there any restrictions on using protected?
import java.util.*;

public class newtree extends newtreeset {

public static void main(String [] args) {
newtree t = new tree();
t.count();
}
}

protected class newtreeset {
void count() {

System.out.println("yes");
}

}

Good to accept that the program will not compile due to

1. " newtree t = new tree(); " Should be newtree t = new newtree();

2. classes can be either public, abstract,final or noaccess modifier. inner classes can be of any access modifier.



santhosh
[ April 21, 2006: Message edited by: santhosh Gopalakrishna Bajja ]

[Ashley Bideau]

Good One

[sirisha sirisha]

this program gives a compiler error, i know that there should be one public class in a file and it should match with the ame of the file.but are there any restrictions on using protected?
import java.util.*;

public class newtree extends newtreeset {

public static void main(String [] args) {
newtree t = new tree();
t.count();
}
}

protected class newtreeset {
void count() {

System.out.println("yes");
}

}

[Venkatesh Rangamani]

Hi sirisha,
A top level class can be either Abstract or Final or Public or a default class. We cannot have a top level class with protected or Private access nodifiers!!