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class A { public static void main(String[] args) { int[] a = new int[10]; int b=0; int x; a[a[b]]=a[b]=b=2; System.out.println(a[x]); //What should be the value of x so that it returns non zero value } }

First note that when the int array is created, each element is initialized to zero.

Basically, in a simple assignment, the left-hand operand is evaluated first to figure out exactly where the value of the right-hand expression should be assigned -- for example, a variable or a particular index of an array. In this case, we have...

int b = 0; a[a[b]] = ...

Here, a[b] is a[0], which is 0. So a[a[b]] is also a[0].

And the line a[a[b]] = a[b] = b = 2 essentially becomes a[0] = (a[0] = (b=2)). So the value 2 is assigned to the variable b, which is assigned to a[0], which is assigned to a[0].

Therefore, a[0] is 2, while a[1] through a[9] are all zeros.

"We're kind of on the level of crossword puzzle writers... And no one ever goes to them and gives them an award." ~Joe Strummer sscce.org

int[] a = new int[10]; int b=0; int x; a[a[b]]=a[b]=b=2; System.out.println(a[x]);

In the above statement first all the variables are fully evaluated and then the assignment happens that is the statement becomes:

a[0]=a[0]=b=2

Since before this statement b=0 and a[b]=0 and as the question ask for a value x of that will give non-zero value, result becomes 0 b'coz that is the only index position where we've stored 2.

class A { public static void main(String[] args) { int[] a = new int[10]; int b=0; int x; a[a[b]]=a[b]=b=2; System.out.println(a[x]); //What should be the value of x so that it returns non zero value } }

in the above program, the variable i is not initialized. and since its a local variable, it does not get the default value. so this above coding results in a compilation error. variable x might not have been initialized

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