String Problem.

[Yogendra Joshi]

Hi Guys ,

I has tried this and i feel that the output is contradictory to my thinking. equals method checks to see if the String literal is "meaningfully equivalent" . Based on that , I wrote a small program to check it. Here's it.

  
class Stringtest 
{
static String a="Yogendra";
static String b="yogendra";
public static void main(String[] args) 
{
if(a.equals(b))
{
System.out.println("Equals Succedded");
}
else
{
System.out.println("Not Succedded !");
}
}
}
  

can you tell me why it goes to else block , when yogendra and Yogendra both does are "MeaningFully Equivalent". This has been nailing me. Please help.

Thanks in Advance.

Yogendra Joshi.

[Scott Johnson]

   
static String a="Yogendra";
static String b="yogendra";

These two strings are not equal because the first character is different. "Y" does not equal "y".

If you want to do a non-casesensitive comparison use this:

   
a.equalsIgnoreCase(b)

[Yogendra Joshi]

Hi Scott ,

Thanks for your immediate reply. I tested and it worked !

Is there any workaround rather then using equalsIgnoreCase ?

Thanks.

Yogendra Joshi.

[wise owen]

Is there any workaround rather then using equalsIgnoreCase?

a.toLowerCase().equals(b.toLowerCase()), and
a.toUpperCase().equals(b.toUpperCase()).

I do not think you want to use them instead of equalsIgnoreCase.