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smita mishra
Ranch Hand

Joined: May 18, 2006
Posts: 31
here is the directory structure:
C:\ dirA\dirB\dirC\A.java
when i try to compile using the command
1:-c:\javac -cp dirA\dirB\dirC\A.java
it displays the error message
javac: no source files
but when i pass this command
2:-c:\java -cp \dirA \dirA\dirB\dirC\A.java
it compiles successfully. what is the difference between 1st command & 2nd command.

if I am inside dirA i.e c:\dirA>
what should I give as classpath variable to complie & execute A.java.
what is relative classpath i.e what is meaning of -cp dirB;dirB\dirC?
if i execute the command c:\dirA> javac -cp dirB;dirB\dirC\A.java.The error message is "javac: no source files is found ".
why did I get this error message when A.java file is inside dirC.
marc weber

Joined: Aug 31, 2004
Posts: 11343

Please do not cross-post. It makes people less inclined to take the time to respond when they find the same question has been answered in another forum.

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subject: classpath
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