will the code give cmpiler error......

[arivu mathi]

public class Test3{
public static void main(String args[]){
System.out.println(method());
}
public static int method(){
try{
throw new Exception();
}
catch(Exception e){
throw new Exception();
}
finally{
return 3;
}
}
}

in one of the mock exam tha answer s compiler error...but it's working fine.....can u plz explain this......

[Finner Jones]

Hi,
It compiles and runs for as well. It looks like the mock has a mistake �?
What mock is it ?

Finner

[ram gaurav]

No , it is not complier error.
But i am not able to understand that like we are throwing the Exception explicitly but on runtime it is not giving any error , it is working fine that is , it is printing 3 as output.
Could you tell me why.

Thanks
Regards
Gaurav

[Barry Gaunt]

public class Test3{
    public static void main(String args[]){
        System.out.println(method());
    }
    public static int method(){
        try{
            throw new Exception();
           }
        catch(Exception e){
            throw new Exception();
        }
        finally{
            return 3;
        }
    }
}

Yes it compiles and produces the output 3.
Where did this question come from? Exactly what Mock Exam?
Please use

tags around your code in future.
[ June 30, 2006: Message edited by: Barry Gaunt ]

[ram gaurav]

No , it is not complier error.
But i am not able to understand that like we are throwing the Exception explicitly but on runtime it is not giving any error , it is working fine that is , it is printing 3 as output.
Could you tell me why.

Thanks
Regards
Gaurav

[Barry Gaunt]

Read JLS 14.20.2. It seems that return 3 is considered an abrupt ending of the finally block so that the second thrown Eception is lost.