explanation needed

Hi all,

wht is the o/p of this?can u explain how the o/p comes?
ans is 1 1 1

System.out.println("1 1 1");

Great,

This is an invisible code:

wow Mark how do you able to see the Code:

Below is the Solution:

Please explain this problem..

Marc,

I think we should now start an Invisible Code Forum too..

And definately I will suggest your name as a bartender

for that forum.

Pls start that as early as possible.

it's called Whitespace, and it is a valid, if somewhat difficult programming language.

ok, but seriously, Suhita, if you want to post the code, we'd all love to help!!!

sorry to all,

this is the code

public class T051 extends Z
{
protected static int x = 0; //1

public static void main(String args[])
{
Z z = new T051();

System.out.println(z.x); //2
}
}

class Z
{
private static int x = 1; //3
}//2

Are you sure that is the correct code?

That code doesn't output what you said.

The output is "1", not "1 1 1". The single println() in main() prints the value of Z.x because the compiler figures out what variable to access during compilation based on the compile-time type of the variable "z". There's no runtime dynamic lookup. Variables (static or not) are never polymorphic.

This is an SCJP question, and as a matter of policy, these get moved to the SCJP forum.

What I mean is there is a compile-time error in that code. I just wondered if they posted the wrong one.

Originally posted by Keith Lynn:
What I mean is there is a compile-time error in that code. I just wondered if they posted the wrong one.

I posted my reply without seeing yours first. But you're right -- Z.x is not accessible in T051.main() because it's private. My answer only holds if Z.x were accessible.