OutPut of abstract class constructor calling method

[abhijit Ohal]

 
abstract class xyz {
    xyz() {
        m1();
    }
    abstract void m1();
}
 
public class abs extends xyz {
    int cnt = 1;
    void m1() {
        System.out.println("" + cnt);
    }
 
    public abs(int cnt) {
        this.cnt = cnt;
    }
 
    public static void main(String[] args) {
        new abs(3);
    }
}
 

 

In Above Code int cnt = 1; then also output is zero. from new abs(3)called abstract class xyz ' constructor it call class abs 'm1 method
What i am thinking is in that time cnt is not initalisied to 1 so it is giving output '0'.Can some one expalain in details.

[Christophe Verré]

Tricky.
Class variable initializers and static initializers of the class will be executed after the superclass initialization.

So when your println is called, members of the subclass are not initialized yet. That's why the default value (0 for an int) is output.

[Sujittt Tripathyrr]

Good Question abhijit ..

thanks

[abhijit Ohal]

Thanks Satou

[Douglas Chorpita]

Yes. Great question!!!