# Shift Operator

Sujittt Tripathyrr
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Posts: 96
what will be the output of this code .

public class ObjectTest {

public static void main(String[] args) {
System.out.println(0 < 1 << 2 >> 1 >>> 2);
}
}

Thanks

Rohit Nath
Ranch Hand
Posts: 387
as of the o/p i am getting = false after compiling.

Rohit Nath
Ranch Hand
Posts: 387

Even I am trying to understand the working..
I tried this..

I got output

true
true
true
false

Keith Lynn
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Posts: 2409
Originally posted by Sujittt Tripathyrr:
what will be the output of this code .

public class ObjectTest {

public static void main(String[] args) {
System.out.println(0 < 1 << 2 >> 1 >>> 2);
}
}

Thanks

Note that the shift operators have precedence over the relational operators, so the type of the result is going to be a boolean.

1 << 2 = 4 >> 1 = 2 >>> 2 = 0

So the expression boils down to

so it prints false.

Rohit Nath
Ranch Hand
Posts: 387
Can you please tell me difference between >> and >>>

>>
op1 >> op2 Shifts bits of op1 right by distance op2; fills with highest (sign) bit on the left side
>>>
op1 >>> op2 Shifts bits of op1 right by distance op2; fills with 0 bits on the left side

What does the bold lettered line mean? "fills with highest (sign) bit"

Daniel Bryant
Ranch Hand
Posts: 54
This essentially boils down to the >> operator leaving the sign of the value shifted the same, i.e. a negative number remains a negative number, and a positive number positive, because the space created at the left of the number after the shift will be filled by the value previously at that location (1 if it was negative, 0 if it was positive) and the >>> operator always making the number positive (by filling the shifted space with a 0)

For example in binary

if we >> shift 1101 by 1 we get 1110
if we >>> shift 1101 by 1 we get 0110

Notice how the sign bit on the second example has altered from 1 to 0.

If you want more information on binary numbers (specifically negative number have a look at Wikipedia here)

Daniel

Aum Tao
Ranch Hand
Posts: 210
Originally posted by Rohit Kharat:
Can you please tell me difference between >> and >>>

>>
op1 >> op2 Shifts bits of op1 right by distance op2; fills with highest (sign) bit on the left side
>>>
op1 >>> op2 Shifts bits of op1 right by distance op2; fills with 0 bits on the left side

What does the bold lettered line mean? "fills with highest (sign) bit"

Here, "fills with highest(sign) bit" refers to the most significant bit(MSB)(i.e. the left most bit). Both the >> and >>> yields the same result for positive numbers, since the MSB is 0. However, when they are applied to negative numbers, their behavior is completely different.

With >>, the sign bit(i.e. 1) is inserted at the MSB.
With >>>, a 0 is inserted at the MSB. So, most often, you always get a positive number.

Rohit Nath
Ranch Hand
Posts: 387
Daniel/Aum,
Thanks for the valuble information!

Sujittt Tripathyrr
Ranch Hand
Posts: 96
Thanks Keith

I understand my doubts.

Thanks to all

Bert Bates
author
Sheriff
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