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Operator precedence

Divya Eknath

Joined: Jul 27, 2006
Posts: 9
Can anybody please tell me the precedence of bitwise/ligical operators:&,^ and |?
In some books its given as & ^ |, while in others it is & | ^.
wise owen
Ranch Hand

Joined: Feb 02, 2006
Posts: 2023
&,^, |

Expressions, Statements, and Blocks
Simeon Cherniy

Joined: Jul 26, 2006
Posts: 21
The order is: & ^ |
x^y = (x | !y) & (!x | y)
That's why the priority of XOR(^) is higher

5-year Student of <br />Moscow Institute of Physics and Technology.
Simeon Cherniy

Joined: Jul 26, 2006
Posts: 21
x^y = (x | y) & (!x | !y)
I agree. Here's the link:
subject: Operator precedence
It's not a secret anymore!