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operators Q

saied ims
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Joined: Jun 21, 2005
Posts: 109
in chapter 4 page 309
class Fork {
public static void main(String[] args) {
if(args.length == 1 | args[1].equals("test")) {
System.out.println("test case");
} else {
System.out.println("production " + args[0]);
And the command-line invocation:
java Fork live2
A. test case
B. production
C. test case live2
D. Compilation fails.
E. An exception is thrown at runtime.
the output will be production Fork

why the answer is E is correct. Because the short circuit (||) is not used, both operands are evaluated. Sinceargs[1] is past the args array bounds, an ArrayIndexOutOfBoundsException is thrown.

Keith Lynn
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Joined: Feb 07, 2005
Posts: 2398
What is the question?
Naseem Khan
Ranch Hand

Joined: Apr 25, 2005
Posts: 809
If you run code by java Fork live2,

args[1].equals("test") will throw ArrayIndexOutOfBoundsException at runtime.

Answer given in the book is correct and the reason is since short circuit or is not used here, even if first condition goes true, second will still be evaluated.

[ August 10, 2006: Message edited by: Naseem Khan ]

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