A nice question

[Roel De Nijs]

what's the output of the following program ?

  
public static void main(String args[]) {
   String obj1 = "SCJP";
   String obj2 = "SCJP"; 
 
   System.out.println("equals: "  + obj1.equals(obj2));
   System.out.println("==: "  + obj1==obj2);
}

[edit] if you want to know the solution (and explanation), just send me a PM, so the fun of other rangers won't be spoiled because solution is in the thread.
[ August 11, 2006: Message edited by: Roel De Nijs ]

[Ivan Rebrov]

what's the output of the following program ?

Cool! Wow!

And jet more interesting the following:

  
 
public class Nice {
public static void main(String args[]) {
String obj1 = "SCJP";
String obj2 = "SCJP";
System.out.println("equals: " + obj1.equals(obj2));
System.out.println("==: " + obj1 == obj[B]1[/B]);
}
}
 

[Praveen Babu]

Its really a nice one.

Bye & Regards,
Praveen

[Justin Yao]

Hello all,
It is really interesting.
[ August 11, 2006: Message edited by: Yao Gao ]

[Rachil Chandran]

Cool Question!!

[Amit Batra]

So are you going to tell us why?

[Ivan Rebrov]

Originally posted by Amitabha Batranab:
So are you going to tell us why?

See this table of operator precedence in Java

http://java.sun.com/docs/books/tutorial/java/nutsandbolts/operators.html

operator "==" has lower precedence then �perator "+"

[Roel De Nijs]

Full explanation

the first line outputs 'equals: true' (i think no explanation needed)
the second line outputs 'false', because the '+' operator has a higher priority then the '==' operator
==> so System.out.println("==: " + obj1==obj2); is equal to System.out.println(("==: " + obj1) == obj2); (pay attention to the braces)
so "==: SCJP" is compared with "SCJP" which returns false of cource

to get the expected output '==: true' you have to change it to
System.out.println("==: " + (obj1==obj2)); (again pay attention to the braces)