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operator precedence

sanjay kumar

Joined: Aug 29, 2006
Posts: 2
I am new to scjp preparation group. so first hi to all..

iam not absolutely clear about operator precedence .

class Sam
static boolean a,b,c,d;
public static void main(String arg[])
d = (a=true) || (b=true) && (c=true);
System.out.println(a +","+b+","+c);

doubt:&& has higher precedence than || then why || is evaluated first.

suggest me a clear guide/tutorial for operator precedence and associativity.
Srikanth Basa
Ranch Hand

Joined: Jun 06, 2005
Posts: 241
So the answer to your question goes as below

Evaluate: ((a=true) || ((b=true) && (c=true)));
Evaluate: ((true) || ((b=true) && (c=true))); // a=true is executed

As it knows true || something is always true (short circuited), the control breaks at this step without executing the further statements for b and c

So the result is a=true b=false and c=false
wise owen
Ranch Hand

Joined: Feb 02, 2006
Posts: 2023
Java Operator Precedence and Associativity Table
What are operator precedence and the order of operand evaluation?
I agree. Here's the link:
subject: operator precedence
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