What they have written is correct. It should be understood that inside the package where the subclass is, only the subclass and the subclasses of it are able to access the protected member which has been declared in any outer subclass as protected...
if you think you can you r right<br />if you think you can not you r double right
[Kathy here, answering the question under Bert's log-in]
I agree with Peter. Sachin, thanks for bringing this up again... I responded in the original thread, but in a nutshell--Peter's correction (and suggestion for improving the wording) is absolutely right!
Spot false dilemmas now, ask me how!
(If you're not on the edge, you're taking up too much room.)