Why Error Here?

[Joe Harry]

Hi Ranchers,

Code below,

public class Conv{
public static void main(String argv[]){ 
Conv c=new Conv(); 
String s=new String("ello"); 
c.amethod(s); 
} 
public void amethod(String s){ 
char c='H'; 
c+=s; 
System.out.println(c); 
} 
}

Why a complie time error?

Regards,
Jothi Shankar Kumar. S

[William Yan]

hi, you mean this? or?

   
        public void amethod(String s) {
char c = 'H';
s = c + s;
System.out.println(s);
}

[Joe Harry]

Hi Above,

I mean the other way,
char c = 'H';
String s = "ello";
c = c + s; //why it gives error here?

Regards,
Jothi Shankar Kumar. S

[Gowher Naik]

public class Conv{
public static void main(String argv[]){ 
Conv c=new Conv(); 
String s=new String("ello"); 
c.amethod(s); 
} 
public void amethod(String s){ 
char c='H'; 
//c+=s; 
s=c+s;  
System.out.println(s); 
} 
}

I have made single change in your code.
Try to find out yourself why there is error.

[William Yan]

Hi,
char is a primitive with 16-bits, why do you think you could stored so fat a String into a char?

[srini p.]

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Hi Kumar,

public void amethod(String s){
char c='H';
c+=s;
System.out.println(c); }

If U observe the code, you are tiring to concatenate a String to char. U can't use "+" operator on a char data (i.e c).

replace the method with
public void amethod(String s){
char c='H';
s+=c;
System.out.println(s); }
It will work !!

Regards,
Srinivas.

[Joe Harry]

Hi all Above,

So a char fits into a String but not the other way. Am I right?

Regards,
Jothi Shankar Kumar. S

[William Yan]

Yes, Jothi,
char is a primitive, but a String is 'like' an array of char.

[Anvi Dixit]

Hi All,

yes the below code is compiling fine but why i am getting the exception
saying : Exception in thread "main" java.lang.NoClassDefFound error

public void amethod(String s){
char c='H';
c+=s;
System.out.println(c); }

If U observe the code, you are tiring to concatenate a String to char. U can't use "+" operator on a char data (i.e c).

replace the method with
public void amethod(String s){
char c='H';
s+=c;
System.out.println(s); }

PLease help me out .
Thanks
Anvi