Why it shows error?

[Joe Harry]

Hi helpers,

Considering the code below,

[B]public class Ref{
public static void main(String argv[]){
          Ref ref = new Ref();
          ref.amethod(ref);
          }
          public void amethod(Ref r){
          int i=99;
          multi(r);
          System.out.println(i);
          }
          public void multi(Ref r){
          ref.i = ref.i*2; //says cannot fine symbol here
          }
}[/B]

So I thought i is local to public void amethod(Ref r), so I declared the variable i right before Ref ref = new Ref(); and even then Iam getting the same error? Can anyone help me on this?

Regards,
Jothi Shankar Kumar. S

[Rajesh Kadle]

Yes, as you said i is local. We should make it class/instance variable to be visible. Please see the change below:

public class Ref{
int i; // this declares a non static variable for class Ref
public static void main(String argv[]){          
Ref ref = new Ref();          
ref.amethod(ref);          
}
          
public void amethod(Ref r){          
int i=99;          
multi(r);          
System.out.println(i);          
}          
 
public void multi(Ref r){          
r.i = r.i*2; //says cannot fine symbol here          
}
 
}

[ October 16, 2006: Message edited by: Rajesh Kadle ]

[Joe Harry]

Hi Rajesh,

Even after making i as an instance variable, I'm getting the same error.

Regards,
Jothi Shankar Kumar. S

[Rajesh Kadle]

you should use 'r' instead of 'ref'. Error is on this variable:

public void multi(Ref r){          
ref.i = ref.i*2; //says cannot fine symbol here          
}

Change the above code to:

public void multi(Ref r){          
r.i = r.i*2; //says cannot fine symbol here          
}